This post contains the answers to the questions in the post http://www.intechgrity.com/understanding-and-writing-pattern-programs-in-ccpp/. I have worked out three different techniques to solve the pattern programs which are both simple and easy. It is advisable to check out all the three techniques to find out the one that is suitable for you. You can solve all the further problems using any of the techniques.
: Pattern 1
n=3 ***** *** * *** *****
: Answer
#include<stdio.h> #include<conio.h> int main(){ int n,i,j,k,l; printf("Enter the no of lines: "); scanf("%d",&n); for(i=0;i<n;i++){ for(j=0;j<=n-i-2;j++){ printf(" "); } for(k=0;k<=i;k++){ printf("%d",k+1); } for(l=i-1;l>=0;l--){ printf("%d",l+1); } printf("\n"); } for(i=0;i<=n-2;i++){ for(j=0;j<=i;j++){ printf(" "); } for(k=0;k<=n-i-2;k++){ printf("%d",k+1); } for(l=n-i-3;l>=0;l--){ printf("%d",l+1); } printf("\n"); } getch(); return 0; }
: Pattern 2
n=4 ******* *** *** ** ** * * ** ** *** *** *******
: Answer
#include<stdio.h> #include<conio.h> int main(){ int n,i,j,k,l; printf("Enter the no of lines: "); scanf("%d",&n); for (i = 1; i <= n; i++){ for (j = n; j >= i; j--){ printf("%d", j); } for (k = 0; k < 2 * (i - 1); k++){ printf(" "); } for (l = i; l <= n; l++){ printf("%d", l); } printf("\n"); } for (i = n; i >= 1; i--){ for (j = n; j >= i; j--){ printf("%d", j); } for (k = 0; k < 2 * (i - 1); k++){ printf(" "); } for (l = i; l <= n; l++){ printf("%d",l); } printf("\n"); } getch(); return 0; }
: Pattern 3
n=4 1 1 33 33 555 555 77777777 555 555 33 33 1 1
: Answer
#include<stdio.h> #include<conio.h> void func(int i, int j, int n){ for (j = 0; j < i / 2 + 1; j++) printf("%d", i); for (j = 0; j < 2 * n - i - 1; j++) printf(" "); for (j = 0; j < i / 2 + 1; j++) printf("%d", i); printf("\n"); } int main(){ int n, i, j; printf("Enter the number of lines: "); scanf("%d", &n); for (i = 1; i <= 2 * n - 1; i = i + 2) func(i, j, n); for (i = 2 * n - 3; i >= 1; i = i - 2) func(i, j, n); getch(); return 0; }
Hopefully you enjoyed reading this tutorial. If you have any doubts please use the comments. Thank you and visit www.intechgrity.com for more tutorials.
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please provide explanation along with the programs
Hi Jeremy
What problems are you facing?
I am beginner in c…and I don’t get the concept of pattern programming.. it is fine till two for loops(I,j) but the third and the fourth are really confusing…please help
Bro if u can explain me pattern 2 in which there are spaces and the value of j in easy steps
*
*
* *
* *
* * *
* *
* *
*
*
how to print this pls open it in text editor
Sry need this pattern
*
*
* *
* *
* *
*
*
use the solution to pattern 1on this page ,replace the ” ” and “*”
can u guide me the below pattern
* * * * * * *
* * * * * *
* * * *
* *
i did’t getting logic behind middle star b/w two triangles in first line
for(int i=4;i>0;i–)
{
for(int k=1;k<=(i*2);k++)
{
System.out.print("*");
}
System.out.println();
}
hii..i awnt print name in star pattron
*****
***
*
***
*****
This pattern program in 5 loops……. please check this and comment.
#include
int main()
{
int i,j,k,n;
printf(“ENter your input”);
scanf(“%d”,&n);
for(i=1;i<=(2*n)-1;i++)
{
//j=2*n-1;
if(i<=n)
{
for(k=1;k=2*i-1;j–)
{
printf(“*”);
}
}
else
{
for(k=2*n-1;k>i;k–)
{
printf(” “);
}
for(j=(2*n)-1;j<=2*i-1;j++)
{
printf("*");
}
}
printf("\n");
}
return 0;
}
need code for this pattern.for n=5
1
2 3
6 5 4
7 8 9 10
15 14 13 12 11
i need code for this question
if n = 1
*
if n = 2
*
*
*
*
*
if n = 3
*
*
**
*
*
*
**
*
*
if n=4
*
*
*
**
*
**
*
*
*
**
*
**
*
*
*
*
generalized code for this pattern
How to print this pattern?
ABCDEFGFEDCBA
ABCDEFFEDCBA
ABCDEEDCBA
ABCDDCBA
ABCCBA
ABBA
AA
Can u help me for pattrn
11
2112
321123
2112
11